ASP.NET中生成Excel遇到的问题及改进方法

/// <summary>
/// 将一组对象导出成EXCEL
/// </summary>
/// <typeparam name="T">要导出对象的类型</typeparam>
/// <param name="objList">一组对象</param>
/// <param name="FileName">导出后的文件名</param>
/// <param name="columnInfo">列名信息</param>
public static void ExExcel<T>(List<T> objList, string FileName, Dictionary<string, string> columnInfo)
{

if (columnInfo.Count == 0) { return; }
if (objList.Count == 0) { return; }
//生成EXCEL的HTML
string excelStr = "";

Type myType = objList[0].GetType();
//根据反射从传递进来的属性名信息得到要显示的属性
List<PropertyInfo> myPro = new List<PropertyInfo>();
foreach (string cName in columnInfo.Keys)
{
PropertyInfo p = myType.GetProperty(cName);
if (p != null)
{
myPro.Add(p);
excelStr += columnInfo[cName] + "\t";
}
}
//如果没有找到可用的属性则结束
if (myPro.Count == 0) { return; }
excelStr += "\n";

foreach (T obj in objList)
{
foreach (PropertyInfo p in myPro)
{
excelStr += p.GetValue(obj, null) + "\t";
}
excelStr += "\n";
}

//输出EXCEL
HttpResponse rs = System.Web.HttpContext.Current.Response;
rs.ContentEncoding = System.Text.Encoding.GetEncoding("GB2312");
rs.AppendHeader("Content-Disposition", "attachment;filename=" + FileName);
rs.ContentType = "application/ms-excel";
rs.Write(excelStr);
rs.End();
}