C语言如何实现红黑树

来源:爱站网时间:2019-12-16编辑:网友分享
我们有时候在看内核的时候会觉得红黑树很有意思,就会想要自己动手去实现,那么你知道C语言如何实现红黑树吗?下面我们就跟着爱站小编一起去看看C语言实现红黑树的方法。

我们有时候在看内核的时候会觉得红黑树很有意思,就会想要自己动手去实现,那么你知道C语言如何实现红黑树吗?下面我们就跟着爱站小编一起去看看C语言实现红黑树的方法。

在看具体的操作的时候有的人可能感觉有些情况是没有考虑到的(如果没有这种感觉的人很有可能根本没有仔细地想)。但是那些“遗漏”的情况如果存在的话,操作之前的红黑树将违反那几个规则。

写代码的时候很多次因为少考虑情况而导致错误,细节比较多,刚开始rb_node中没有指向父节点的指针,写的快吐血,然后还是加上了。代码具体的含义可以结合文章和注释来看(还是很好理解的)。下面的代码中可能还有没有考虑到的细节,欢迎拍砖。

 

 

#include <stdio.h>
#include <stdlib.h>

 

const int RED = 0;
const int BLACK = 1;

struct rb_node{
    rb_node* lchild, *rchild, *parent;
    int key, colour;
};
rb_node* root;

rb_node* get_node(rb_node* parent, int key);
void rb_insert(int key);
rb_node* rb_search(int key);
void rb_delete(int key);
rb_node* clock_wise(rb_node* node);
rb_node* counter_clock_wise(rb_node* node);
void show_rb_tree(rb_node* node);

rb_node* get_node(rb_node* parent, int key){
    rb_node *tmp = (rb_node*)malloc(sizeof(rb_node));
    tmp->key = key;
    tmp->colour = RED;
    tmp->parent = parent;
    tmp->lchild = tmp->rchild = NULL;
    return tmp;
}

rb_node* clock_wise(rb_node* node){
    if(node == NULL || node->lchild == NULL)
    return NULL;

    rb_node *rb_1=node, *rb_2=node->lchild, *rb_3=node->lchild->rchild;
    if(rb_1->parent != NULL){
    if(rb_1->parent->lchild == rb_1)
        rb_1->parent->lchild = rb_2;
    else
        rb_1->parent->rchild = rb_2;
    }else if(rb_1 == root){
    root = rb_2;
    }
    rb_2->parent = rb_1->parent;

    rb_1->parent = rb_2;
    rb_2->rchild = rb_1;

    rb_1->lchild = rb_3;
    if(rb_3 != NULL)rb_3->parent = rb_1;

    return rb_2;   
}

rb_node* counter_clock_wise(rb_node* node){
    if(node == NULL || node->rchild == NULL)
    return NULL;

    rb_node *rb_1=node, *rb_2=node->rchild, *rb_3=node->rchild->lchild;
    if(rb_1->parent != NULL){
    if(rb_1->parent->lchild == rb_1)
        rb_1->parent->lchild = rb_2;
    else
        rb_1->parent->rchild = rb_2;
    }
    else if(rb_1 == root){
    root = rb_2;
    }
    rb_2->parent = rb_1->parent;

    rb_1->parent = rb_2;
    rb_2->lchild = rb_1;

    rb_1->rchild = rb_3;
    if(rb_3 != NULL)rb_3->parent = rb_1;

    return rb_2;
}

rb_node* rb_search(int key){
    rb_node *p = root;
    while(p != NULL){
    if(key < p->key)
        p = p->lchild;
    else if(key > p->key)
        p = p->rchild;
    else
        break;
    }
    return p;
}

void rb_insert(int key){
    rb_node *p=root, *q=NULL;

    if(root == NULL){
    root = get_node(NULL, key);
    root->colour = BLACK;
    return;
    }

    while(p != NULL){
    q = p;
    if(key < p->key)
        p = p->lchild;
    else if(key > p->key)
        p = p->rchild;
    else return;
    }

    if(key < q->key)
    q->lchild = get_node(q, key);
    else
    q->rchild = get_node(q, key);

    while(q != NULL && q->colour == RED){
    p = q->parent;//p won't null, or BUG.

    if(p->lchild == q){
        if(q->rchild != NULL && q->rchild->colour == RED)
        counter_clock_wise(q);       
        q = clock_wise(p);
        q->lchild->colour = BLACK;
    }
    else{
        if(q->lchild != NULL && q->lchild->colour == RED)
        clock_wise(q);
        q = counter_clock_wise(p);
        q->rchild->colour = BLACK;
    }

    q = q->parent;
    }
    root->colour = BLACK;
}

void show_rb_tree(rb_node* node){
    if(node == NULL)
    return;
    printf("(%d,%d)\n", node->key, node->colour);
    if(node->lchild != NULL){
    printf("[-1]\n");
    show_rb_tree(node->lchild);
    }
    if(node->rchild != NULL){
    printf("[1]\n");
    show_rb_tree(node->rchild);
    }
    printf("[0]\n");
}

void rb_delete(int key){
    rb_node *v = rb_search(key), *u, *p, *c, *b;
    int tmp;
    if(v == NULL) return;

    u = v;
    if(v->lchild != NULL && v->rchild != NULL){
    u = v->rchild;
    while(u->lchild != NULL){
        u = u->lchild;
    }
    tmp = u->key;
    u->key = v->key;
    v->key = tmp;
    }

    //u is the node to free.
    if(u->lchild != NULL)
    c = u->lchild;
    else
    c = u->rchild;

    p = u->parent;
    if(p != NULL){
    //remove u from rb_tree.
    if(p->lchild == u)
        p->lchild = c;
    else
        p->rchild = c;
    }
    else{
    //u is root.
    root = c;
    free((void*)u);
    return;
    }

    //u is not root and u is RED, this will not unbalance.
    if(u->colour == RED){
    free((void*)u);
    return;
    }

    free((void*)u);
    u = c;

    //u is the first node to balance.
    while(u != root){
    if(u != NULL && u->colour == RED){
        //if u is RED, change it to BLACK can finsh.
        u->colour = BLACK;
        return;
    }

    if(u == p->lchild)
        b = p->rchild;
    else
        b = p->lchild;

    printf("%d\n", b->key);

    //b is borther of u. b can't be null, or the rb_tree is must not balance.
    if(b->colour == BLACK){
        //If b's son is RED, rotate the node.
        if(b->lchild != NULL && b->lchild->colour == RED){
        if(u == p->lchild){
            b = clock_wise(b);
            b->colour = BLACK;
            b->rchild->colour = RED;

            p = counter_clock_wise(p);
            p->colour = p->lchild->colour;
            p->lchild->colour = BLACK;
            p->rchild->colour = BLACK;
        }
        else{
            p = clock_wise(p);
            p->colour = p->rchild->colour;
            p->rchild->colour = BLACK;
            p->lchild->colour = BLACK;
        }

        return;
        }
        else if(b->rchild != NULL && b->rchild->colour == RED){
        if(u == p->rchild){
            b = counter_clock_wise(b);
            b->colour = BLACK;
            b->lchild->colour = RED;

            p = clock_wise(p);
            p->colour = p->rchild->colour;
            p->rchild->colour = BLACK;
            p->lchild->colour = BLACK;
        }
        else{
            p = counter_clock_wise(p);
            p->colour = p->lchild->colour;
            p->lchild->colour = BLACK;
            p->rchild->colour = BLACK;
        }       
        return;
        }
        else{//if b's sons are BLACK, make b RED and move up u.
        b->colour = RED;
        u = p;
        p = u->parent;
        continue;
        }
    }
    else{
        if(u == p->lchild){
        p = counter_clock_wise(p);
        p->colour = BLACK;
        p->lchild->colour = RED;
        p = p->lchild;
        }
        else{
        p = clock_wise(p);
        p->colour = BLACK;
        p->rchild->colour = RED;
        p = p->rchild;
        }
    }
    }
    root->colour = BLACK;
}

int main(){
    int i;
    root = NULL;
    for(i = 1; i <= 10; i++){   
    rb_insert(i);
    }
    rb_delete(9);
    rb_delete(3);
    rb_delete(7);
    show_rb_tree(root);
    printf("\n");
    return 0;
}

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