如何将xml转换为java字符串列表

问题描述

我在Java中有一个xml字符串，我需要将其分解为较小的字符串。例如，给出以下内容：

LokeshGuptaIndiaAlexGussinRussiaDavidFeezorUSA

我如何在没有明显分隔符的情况下进行解析以获取：

string1 = "LokeshGuptaIndia"
string2 = "AlexGussinRussia"
string3 = "DavidFeezorUSA"

任何想法都值得赞赏。谢谢！

思路一：

您可以将XML解析为DOM，迭代根元素的子节点（一旦向XML添加一个，然后将每个元素呈现为XML。

String xml = " \r\n" + 
             "    \r\n" + 
             "    Lokesh    \r\n" + 
             "    Gupta     \r\n" + 
             "    India   \r\n" + 
             " \r\n" + 
             "    \r\n" + 
             "    Alex    \r\n" + 
             "    Gussin    \r\n" + 
             "    Russia    \r\n" + 
             " \r\n" + 
             "    \r\n" + 
             "    David    \r\n" + 
             "    Feezor    \r\n" + 
             "    USA    \r\n" + 
             "";

// Add missing root element
xml = xml.replaceAll("^()?", "$1") + "";

// Prepare parser
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder domBuilder = domFactory.newDocumentBuilder();
Document document = domBuilder.parse(new InputSource(new StringReader(xml)));

// Prepare renderer
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");

// Iterate top-level elements and render them to individual strings
List list = new ArrayList();
for (Node node = document.getDocumentElement().getFirstChild(); node != null; node = node.getNextSibling()) {
    if (node.getNodeType() == Node.ELEMENT_NODE) {
        StringWriter buf = new StringWriter();
        transformer.transform(new DOMSource(node), new StreamResult(buf));
        String elementXml = buf.toString();
        elementXml = elementXml.replaceAll("\\R", " ").trim(); // Eliminate line separators
        list.add(elementXml);
    }
}

// Print the result
for (String s : list)
    System.out.printf("'%s'%n", s);

输出

'LokeshGuptaIndia'
'AlexGussinRussia'
'DavidFeezorUSA'

思路二：

您可以使用StAX进行：

private ArrayList  getEmployees(String input) throws XMLStreamException {
    ArrayList  employees = new ArrayList ();

    XMLEventReader xmlEventReader = XMLInputFactory.newInstance().createXMLEventReader(new StringReader(input));
    XMLOutputFactory xmlOutputFactory = XMLOutputFactory.newInstance();

    XMLEventWriter xmlEventWriter = null;
    StringWriter sw = null;
    while (xmlEventReader.hasNext()) {
        XMLEvent xmlEvent = xmlEventReader.nextEvent();
        if(xmlEvent.isStartElement() && xmlEvent.asStartElement().getName().getLocalPart().equals("employee"))  {
            sw = new StringWriter();
            xmlEventWriter = xmlOutputFactory.createXMLEventWriter(sw);
        }

        if(xmlEventWriter != null) {
            if(xmlEvent.isCharacters() && xmlEvent.asCharacters().isWhiteSpace()) {
                continue;
            }

            xmlEventWriter.add(xmlEvent);
        }

        if(xmlEvent.isEndElement() && xmlEvent.asEndElement().getName().getLocalPart().equals("employee")) {
            xmlEventWriter.close();
            employees.add(sw.toString());
            xmlEventWriter = null;
            sw = null;
        }
    }

    return employees;
}

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