“来自套接字的“无尽” AudioInputStream是什么

来源:爱站网时间:2021-11-17编辑:网友分享
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问题描述


我在从Socket创建AudioInputStream时遇到问题。这是重要的部分:

public class SoundStream extends Thread {
    private int port;
    private String IP;
    private Socket socket;

    private SoundObject soundObject;

    private OpenAL openAL;
    private Source source;

    private boolean run = true;

    public SoundStream(int port, String IP, SoundObject soundObject) {
        this.soundObject = soundObject;
        this.port = port;
        this.IP = IP;
    }

    public void run() {
        try {
            this.socket = new Socket(this.IP, this.port);
            this.openAL = new OpenAL();
        } catch (Exception e) {
            e.printStackTrace();
        }
        this.mainCycleMethod();
    }

    private void mainCycleMethod() {
        while (run) {
            this.soundObject.blockAndWait();
            switch (this.soundObject.getAndResetEvent()) {
                case 0:
                    this.run = false;
                    this.close();
                    break;
                case 1:
                    this.setPitch();
                    break;
                case 2:
                    this.closeSource();
                    this.play();
                    break;
                case 3:
                    this.pause(true);
                    break;
                case 4:
                    this.pause(false);
                    break;
            }
        }
    }

    private BufferedInputStream getInputStream() throws Exception {
        return new BufferedInputStream(socket.getInputStream());
    }

    private void setPitch() {
        if(this.source != null) {
            try {
                this.source.setPitch(this.soundObject.getPitch());
            } catch (ALException e) {
                e.printStackTrace();
            }
        }
    }

    private void play() {
        try {
            AudioInputStream audioInputStream = new AudioInputStream(this.getInputStream(), this.soundObject.getAudioFormat(), AudioSystem.NOT_SPECIFIED);
//            AudioInputStream audioInputStream_tmp = AudioSystem.getAudioInputStream(this.getInputStream());
//            AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(this.soundObject.getAudioFormat(), audioInputStream_tmp);
            this.source = openAL.createSource(audioInputStream);
            this.source.setGain(1f);
            this.source.play();
        } catch (Exception ex) {
            ex.printStackTrace();
        }
    }

    private void close() {
        this.closeSource();
        this.openAL.close();
        try {
            this.socket.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    private void closeSource() {
        if(this.source!=null) {
            this.source.close();
        }
    }

    private void pause(boolean pause) {
        if(this.source != null) {
            try {
                if (pause) {
                    this.source.pause();
                } else {
                    this.source.play();
                }
            } catch (ALException ex) {
                ex.printStackTrace();
            }
        }
    }
}


public class SoundObject extends AbstractEventObject {
    public AudioFormat getAudioFormat() {
        boolean signed = false;
        //true,false
        boolean bigEndian = false;
        //true,false
        return new AudioFormat(this.frequency, this.bits, this.channels, signed, bigEndian);
    }
.
.
.
.
}

此代码在此行引发UnsupportedAudioFileException:

AudioInputStream audioInputStream_tmp = AudioSystem.getAudioInputStream(this.getInputStream());

但是,当我使用此代码时:

AudioInputStream audioInputStream = new AudioInputStream(this.getInputStream(), this.soundObject.getAudioFormat(), 100000);

它播放声音,但只有在将这100000个样本帧加载到音频输入流之后才播放。播放所有100000帧后,完成。

我想,如果我可以在第一次AudioInputStream初始化期间直接将AudioFormat作为参数传递,那么我将解决此问题,但是似乎不可能。我正在从服务器接收音频格式规范。

我认为一种可能的解决方案是创建一条数据线,我可以将其作为参数传递给AudioInputStream构造函数。但是我不确定如何将数据直接从套接字获取到数据线。我知道一个使用无限循环的解决方案,它可以读取数据并将其写入数据线。但这似乎是浪费。是否有更直接的方法?

我希望可以使用java-openAL库来解决,因为我需要更改速度,并且希望我自己不必这样做。

谢谢

解决方法:


我终于解决了这个问题。事实证明,java-openAL内置了流支持,但是它不在GitHub的文档中,因此我一开始没有注意到。 Source类中有一个createOutputStream方法,该方法返回OutputStream。您可以将字节直接写入OutputStream。

这是我的代码:

在此代码段中,我初始化OpenAL:

public void run() {
    try {
        this.socket = new Socket(this.IP, this.port);
        this.openAL = new OpenAL();
    } catch (Exception ex) {
        Log.severe(ex.toString());
    }
    this.mainCycleMethod();
}

这是我的play方法,当InputStream可用时会调用:

private void play() {
    try {
        this.source = openAL.createSource();
        this.outputWriter = new OutputWriter(this.socket.getInputStream(), this.source, this.soundObject.getAudioFormat());
        this.source.setGain(1f);
        this.outputWriter.start();
    } catch (Exception ex) {
        Log.severe(ex.toString());
    }
}

您必须使用不带参数的createSource方法,它会返回Source的新实例。不要在源代码上调用play方法,它由SourceOutputStream类处理,该实例由createOutputStream方法返回。手动调用play方法没有什么问题,但是当缓冲区为空时,我的经验很差。基本上,以后开始将数据流传输到OpenAL时,它不会开始播放。

这是我的OutputWriter代码,它负责将字节从InputStream传递到OutputStream:

package cz.speechtech.sound;

import org.urish.openal.ALException;
import org.urish.openal.Source;

import javax.sound.sampled.AudioFormat;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;

/**
 * Created by honza on 16.12.15.
 */
public class OutputWriter extends Thread {
    private InputStream inputStream;
    private OutputStream outputStream;

    private int STREAMING_BUFFER_SIZE = 24000;
    private int NUMBER_OF_BUFFERS = 4;

    private boolean run = true;

    public OutputWriter(InputStream inputStream, Source source, AudioFormat audioFormat) {
        this.inputStream = inputStream;
        try {
            this.outputStream = source.createOutputStream(audioFormat, this.NUMBER_OF_BUFFERS, 1024);
        } catch (ALException e) {
            e.printStackTrace();
        }
    }

    public void run() {
        byte[] buffer = new byte[this.STREAMING_BUFFER_SIZE];
        int i;
        try {
            Thread.sleep(1000); // Might cause problems
            while (this.run) {
                i = this.inputStream.read(buffer);
                if (i == -1) break;
                outputStream.write(buffer, 0, i);
            }
        } catch (IOException e) {
            e.printStackTrace();
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }

    public synchronized void stopRunning() {
        this.run = false;
        try {
            this.outputStream.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

}

祝您有美好的一天。

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